An equilateral triangle is inscribed in a parabola x^{2}=\sqrt{3}y where one vertex of the triangle is at the vertex of the parabola. If p is the length of side of the triangle and q is the length of the latus rectum, then which one of the following is correct?

  1. A. p=q
  2. B. p=\sqrt{3}q
  3. C. p=2\sqrt{3}q
  4. D. 2\sqrt{3}p=q

Correct Answer: C. p=2\sqrt{3}q

Explanation

The parabola is x^2 = \sqrt{3}y, so its latus rectum is q = \sqrt{3}. Let the vertices of the equilateral triangle be (0,0) and (\pm \frac{p}{2}, \frac{p\sqrt{3}}{2}). Substituting the coordinates of one vertex into the parabola's equation gives (\frac{p}{2})^2 = \sqrt{3}(\frac{p\sqrt{3}}{2}) \implies \frac{p^2}{4} = \frac{3p}{2}, which gives p = 6. Since q = \sqrt{3}, we have p = 2\sqrt{3}(\sqrt{3}) = 2\sqrt{3}q.

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