A railway wagon (open at the top) of mass M_{1} is moving with speed v_{1} along a straight track. As a result of rain, after some time it gets partially filled with water so that the mass of the wagon becomes M_{2} and speed becomes v_{2} Taking the rain to be falling vertically and water stationary inside the wagon, the relation between the two speeds v_{1} and v_{2} is:
- A. v_{1}=v_{2}
- B. \frac{1}{2}M_{1}v_{1}^{2} \lt \frac{1}{2}M_{2}v_{2}^{2}
- C. M_{1}v_{1}=M_{2}v_{2} ✓
- D. M_{1}v_{1} \lt M_{2}v_{2}
Correct Answer: C. M_{1}v_{1}=M_{2}v_{2}
Explanation
Since rain falls vertically, there is no external horizontal force acting on the wagon. Therefore, horizontal momentum is conserved: M_{1}v_{1} = M_{2}v_{2}.
Related questions on Physics
- The commercial unit of electrical energy is kilowatt-hour (kWh), which is equal to
- Which one of the following statements regarding a current-carrying solenoid is <strong>NOT</strong> correct?
- An object is made of two equal parts by volume; one part has density \rho_{0} and the other part has density 2\rho_{0}. What is the aver...
- A pressure cooker cooks food faster by
- Which one of the following wavelengths corresponds to the wavelength of X-rays?