Sand falls vertically on a conveyor belt at a rate of 0.1\text{ kg/s}. In order to keep the belt moving at a uniform speed of 2\text{ m/s}, the force required to be applied on the belt is:
- A. 0\text{ N}
- B. 0.2\text{ N} ✓
- C. 1.0\text{ N}
- D. 2.0\text{ N}
Correct Answer: B. 0.2\text{ N}
Explanation
Force required F = v \cdot \frac{dm}{dt} = 2 \times 0.1 = 0.2\text{ N}.
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