One block of 2.0\text{ kg} mass is placed on top of another block of 3.0\text{ kg} mass. The coefficient of static friction between the two blocks is 0.2. The bottom block is pulled with a horizontal force F such that both the blocks move together without slipping. Taking acceleration due to gravity as 10\text{ m/s}^{2}, the maximum value of the frictional force is :

  1. A. 50\text{ N}
  2. B. 30\text{ N}
  3. C. 4\text{ N} ✓
  4. D. 10\text{ N}

Correct Answer: C. 4\text{ N}

Explanation

The maximum static frictional force f_{max} = \mu \cdot N = 0.2 \times (2.0 \times 10) = 4\text{ N}.

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