Match List I with List II and select the correct answer using the code given below the Lists: \begin{array}{|l|l|} \hline \textbf{List I (Chemical process)} & \textbf{List II (Reaction)} \\ \hline \text{A. Electrolysis of water} & \text{1. Double displacement reaction} \\ \hline \text{B. Burning of coal} & \text{2. Combination reaction} \\ \hline \text{C. Iron nail immersed in copper sulphate solution} & \text{3. Decomposition reaction} \\ \hline \text{D. Addition of barium chloride solution to aluminium sulphate solution} & \text{4. Displacement reaction} \\ \hline \end{array} Code: A B C D

  1. A. 3 4 2 1
  2. B. 4 2 1 3
  3. C. 3 2 4 1 ✓
  4. D. 4 1 2 3

Correct Answer: C. 3 2 4 1

Explanation

Electrolysis of water is a decomposition reaction (A-3). Burning of coal is combination (B-2). Iron in copper sulphate is displacement (C-4). Barium chloride with aluminium sulphate is double displacement (D-1).

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