The motion of a particle of mass m is described by the relation, y=ut-\frac{1}{2}gt^{2}, where u is the initial velocity of the particle. The force acting on the particle is
- A. F=m(\frac{du}{dt})
- B. F=mg
- C. F=m(\frac{dy}{dt})
- D. F=-mg ✓
Correct Answer: D. F=-mg
Explanation
Acceleration is the second derivative of displacement with respect to time. a = \frac{d^{2}y}{dt^{2}} = -g. Therefore, force F = ma = -mg.
Related questions on Physics
- The commercial unit of electrical energy is kilowatt-hour (kWh), which is equal to
- Which one of the following statements regarding a current-carrying solenoid is <strong>NOT</strong> correct?
- An object is made of two equal parts by volume; one part has density \rho_{0} and the other part has density 2\rho_{0}. What is the aver...
- A pressure cooker cooks food faster by
- Which one of the following wavelengths corresponds to the wavelength of X-rays?