What is g(15) equal to?

Consider the following for the next two (02) items that follow: Let f(x)=x^{2}-1 and g(f(x))=x-\sqrt{x}+1.

  1. A. 1
  2. B. 2
  3. C. 3
  4. D. 4

Correct Answer: C. 3

Explanation

From the previous question, we established g(x) = \sqrt{x+1} - \sqrt{x+1} + 1. Substituting x=15: g(15) = \sqrt{16} - \sqrt{16} + 1 = 4 - 2 + 1 = 3.

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