What is the <strong>MAXIMUM</strong> value of y?
Consider the following for the next two (02) items that follow: Given that 4x^{2}+y^{2}=9.
- A. \frac{3}{2}
- B. 3 ✓
- C. 4
- D. 6
Correct Answer: B. 3
Explanation
The given equation is 4x^2 + y^2 = 9. Since x^2 \geq 0, it follows that 4x^2 \geq 0. Therefore, y^2 = 9 - 4x^2 \leq 9. This means -3 \leq y \leq 3. The maximum possible value for y is 3.
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