What is the oxidation state of Vanadium in V_{2}O_{5}?
- A. +2
- B. +4
- C. +3
- D. +5 ✓
Correct Answer: D. +5
Explanation
Let the oxidation state of Vanadium be x. In V_{2}O_{5}, oxygen has an oxidation state of -2. Hence, 2x + 5(-2) = 0, which yields x = +5.
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