Escape speed from the Earth is close to 11.2 \text{ km s}^{-1}. On another planet whose radius is half of the Earth's radius and whose mass density is four times that of the Earth, the escape speed in \text{km s}^{-1} will be close to :

  1. A. 11.2
  2. B. 15.8
  3. C. 5.6
  4. D. 7.9

Correct Answer: A. 11.2

Explanation

Escape velocity v_e \propto R\sqrt{\rho}. If radius R is halved and density \rho is quadrupled, the escape velocity becomes (1/2)\sqrt{4} \times v_e = v_e. It remains 11.2 \text{ km s}^{-1}.

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