Escape speed from the Earth is close to 11.2 \text{ km s}^{-1}. On another planet whose radius is half of the Earth's radius and whose mass density is four times that of the Earth, the escape speed in \text{km s}^{-1} will be close to :
- A. 11.2 ✓
- B. 15.8
- C. 5.6
- D. 7.9
Correct Answer: A. 11.2
Explanation
Escape velocity v_e \propto R\sqrt{\rho}. If radius R is halved and density \rho is quadrupled, the escape velocity becomes (1/2)\sqrt{4} \times v_e = v_e. It remains 11.2 \text{ km s}^{-1}.
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