A block of mass 2 kg, moving with the initial speed of 3 m/s comes to rest on a rough horizontal surface after travelling a distance of 3 m. The magnitude of the frictional force is :
- A. 9 N
- B. 3 N ✓
- C. 18 N
- D. 1 N
Correct Answer: B. 3 N
Explanation
Using the equation of motion v^2 = u^2 + 2as, we get 0 = 3^2 + 2a(3), giving a = -1.5 \text{ m/s}^2. The frictional force F = ma = 2 \times 1.5 = 3 \text{ N}.
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