What is the <strong>MAXIMUM</strong> value of P(A)+P(B)?
Consider the following for the next two (02) items that follow : Let A and B be two events such that P(A\cup B)\geq 0.75 and 0.125\leq P(A\cap B)\leq 0.375.
- A. 0.75
- B. 1.125
- C. 1.375 ✓
- D. 1.625
Correct Answer: C. 1.375
Explanation
Using the relation P(A) + P(B) = P(A \cup B) + P(A \cap B), we maximize the sum by maximizing both terms. The maximum possible value for any probability P(A \cup B) is 1. The given maximum for P(A \cap B) is 0.375. Therefore, the maximum value of P(A) + P(B) is 1 + 0.375 = 1.375.
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