What is the mean deviation of the largest five observations ?
Consider the following for the next two (02) items that follow : The marks obtained by 10 students in a Statistics test are 24, 47, 18, 32, 19, 15, 21, 35, 50 and 41.
- A. 4.8
- B. 5.5
- C. 6 ✓
- D. 7.5
Correct Answer: C. 6
Explanation
The largest five observations are 32, 35, 41, 47, 50. Their mean is \bar{x} = \frac{32 + 35 + 41 + 47 + 50}{5} = \frac{205}{5} = 41. The absolute deviations from the mean are |32-41|=9, |35-41|=6, |41-41|=0, |47-41|=6, |50-41|=9. The mean deviation is the average of these absolute deviations: \frac{9 + 6 + 0 + 6 + 9}{5} = \frac{30}{5} = 6.
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