Two resistances of 5.0 \Omega and 7.0 \Omega are connected in series and the combination is connected in parallel with a resistance of 36.0 \Omega. The equivalent resistance of the combination of three resistors is
- A. 24.0 \Omega
- B. 12.0 \Omega
- C. 9.0 \Omega ✓
- D. 6.0 \Omega
Correct Answer: C. 9.0 \Omega
Explanation
The equivalent resistance of the series combination is 5.0 + 7.0 = 12.0 \Omega. When this is connected in parallel with 36.0 \Omega, the total equivalent resistance is (12 \times 36) / (12 + 36) = 432 / 48 = 9.0 \Omega.
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