The vectors \vec{a}, \vec{b} and \vec{c} are of the same length. If taken pairwise, they form equal angles. If \vec{a}=\hat{i}+\hat{j} and \vec{b}=\hat{j}+\hat{k}, then what can \vec{c} be equal to? I. \hat{i}+\hat{k} II. \frac{-\hat{i}+4\hat{j}-\hat{k}}{3} Select the correct answer using the code given below.
- A. I only
- B. II only
- C. Both I and II ✓
- D. Neither I nor II
Correct Answer: C. Both I and II
Explanation
Both \vec{a} and \vec{b} have length \sqrt{2}. The angle between them satisfies \cos\theta = \frac{1}{2}. For option I, \vec{c} = \hat{i}+\hat{k} has length \sqrt{2} and yields \vec{a}\cdot\vec{c}=1 and \vec{b}\cdot\vec{c}=1, so it forms the same angle. For option II, \vec{c} = \frac{-\hat{i}+4\hat{j}-\hat{k}}{3} has length \frac{\sqrt{1+16+1}}{3} = \sqrt{2}, and yields \vec{a}\cdot\vec{c} = \frac{-1+4}{3} = 1 and \vec{b}\cdot\vec{c} = \frac{4-1}{3} = 1. Both vectors satisfy the given conditions.
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