What is the <strong>MINIMUM</strong> value of the function f(x)=\log_{10}(x^{2}+2x+11)?

Explanation

Rewrite the quadratic expression inside the logarithm by completing the square: x^2+2x+11 = (x+1)^2+10. Since (x+1)^2 \geq 0, the minimum value of the quadratic is 10. Therefore, the minimum value of the function is \log_{10}(10) = 1.

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