What is \lim_{x\rightarrow\frac{\pi}{2}}(\sec x-\tan x) equal to?

  1. A. -1
  2. B. 0
  3. C. 1/2
  4. D. 1

Correct Answer: B. 0

Explanation

Convert the expression to sines and cosines: \lim_{x \to \pi/2} \left(\frac{1}{\cos x} - \frac{\sin x}{\cos x}\right) = \lim_{x \to \pi/2} \frac{1-\sin x}{\cos x}. Using L'Hopital's rule, differentiate the numerator and denominator to get \lim_{x \to \pi/2} \frac{-\cos x}{-\sin x} = \frac{0}{-1} = 0.

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