What is f(0.999)+f(1.001) equal to?
Direction: Consider the following for the two (02) items that follow : Let f(x)=[x]^{2}-[x^{2}].
- A. -1
- B. 0 ✓
- C. 1
- D. 2
Correct Answer: B. 0
Explanation
For x=0.999, [0.999]=0 and [0.999^2]=[0.998001]=0, so f(0.999) = 0^2 - 0 = 0. For x=1.001, [1.001]=1 and [1.001^2]=[1.002001]=1, so f(1.001) = 1^2 - 1 = 0. The sum is 0+0=0.
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