What is the equation of the plane passing through the point (1, 1, 1) and perpendicular to the line whose direction ratios are (3, 2, 1)?

Explanation

The direction ratios of the normal to the plane are (3, 2, 1). The equation of the plane passing through (1, 1, 1) is given by 3(x-1) + 2(y-1) + 1(z-1) = 0 \implies 3x-3 + 2y-2 + z-1 = 0 \implies 3x+2y+z=6.

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