If p+q=10, then what is \frac{dy}{dx} equal to?
Consider the following for the two (02) items that follow : Let (x+y)^{p+q}=x^{p}y^{q}, where p, q are positive integers.
- A. y/x ✓
- B. xy
- C. x^{10}y^{10}
- D. (y/x)^{10}
Correct Answer: A. y/x
Explanation
As established, for any relationship of the form (x+y)^{p+q}=x^p y^q, implicit differentiation always results in \frac{dy}{dx} = \frac{y}{x}, regardless of the specific values of p and q.
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