If two fair dice are tossed, then what is the probability that the sum of the numbers on the faces of the dice is <strong>STRICTLY GREATER THAN</strong> 7?
- A. 1/3
- B. 5/12 ✓
- C. 7/12
- D. 3/4
Correct Answer: B. 5/12
Explanation
When two dice are tossed, total outcomes = 36. Favourable outcomes for sum \gt 7 are sums of 8, 9, 10, 11, and 12, which correspond to 5, 4, 3, 2, and 1 ways respectively. Total favourable outcomes = 15. Probability = 15/36 = 5/12.
Related questions on Statistics & Probability
- Let x be the mean of squares of first n natural numbers and y be the square of mean of first n natural numbers. If $\frac{x}{y}=\fra...
- What is the probability of getting a composite number in the list of natural numbers from 1 to 50?
- Two numbers x and y are chosen at random from a set of first 10 natural numbers. What is the probability that (x+y) is divisible by 4?
- A number x is chosen at random from first n natural numbers. What is the probability that the number chosen satisfies $x+\frac{1}{x} \gt...
- Three fair dice are tossed once. What is the probability that they show different numbers that are in AP?