An urn contains 5 white, 6 red and 4 blue balls. Three balls are drawn at random. What is the probability that a white ball, a red ball and a blue ball are drawn?

Explanation

The total number of balls is 15. The total number of ways to draw 3 balls is \binom{15}{3} = 455. The number of ways to draw one ball of each color is \binom{5}{1} \times \binom{6}{1} \times \binom{4}{1} = 5 \times 6 \times 4 = 120. The required probability is \frac{120}{455} = \frac{24}{91}.

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