Three faces of a die are black, two faces are white and one face is red. The die is tossed three times. What is the probability that the colours black, white and red appear in the first, second and third tosses respectively?

Explanation

The probabilities for each toss are independent. The probability of getting black on the first toss is P(B) = \frac{3}{6} = \frac{1}{2}. The probability of white on the second toss is P(W) = \frac{2}{6} = \frac{1}{3}. The probability of red on the third toss is P(R) = \frac{1}{6}. The combined probability is \frac{1}{2} \times \frac{1}{3} \times \frac{1}{6} = \frac{1}{36}.

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