Consider the following pairs of reactions and properties : <table border='1' cellpadding='6' cellspacing='0'> <tr><th>Reactions</th><th>Properties</th></tr> <tr><td>I. Fe(s) + 2HCl(aq) \rightarrow FeCl_2(aq) + H_2(g)</td><td>Fe is reductant</td></tr> <tr><td>II. Zn(s) + CuSO_4(aq) \rightarrow ZnSO_4(aq) + Cu(s)</td><td>Cu is being reduced</td></tr> <tr><td>III. Br_2(l) + 2I^-(aq) \rightarrow 2Br^-(aq) + I_2(s)</td><td>Br_2 is reductant</td></tr> <tr><td>IV. CH_4(g) + 2O_2(g) \rightarrow CO_2(g) + 2H_2O(l)</td><td>C atom in CH_4 is oxidized</td></tr> </table> Which of the above pairs are correct?
- A. I and II only
- B. II, III and IV
- C. I, II and IV ✓
- D. I, III and IV
Correct Answer: C. I, II and IV
Explanation
In reaction I, Fe loses electrons (oxidized) so it acts as a reductant. In reaction II, Cu2+ in CuSO4 gains electrons and is reduced to Cu. In reaction IV, the carbon atom in CH4 is oxidized to CO2. However, in reaction III, Br2 gains electrons (reduced) so it acts as an oxidant, not a reductant.
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