What is \( \lim_{x \to 1} \frac{x^{(n^2 - 1)} - 1}{x^{(n+1)} - 1} \) equal to, where \( n > 1 \) is a natural number ?
- A. 0
- B. 1
- C. n - 1 ✓
- D. n + 1
Correct Answer: C. n - 1
Explanation
Applying L'Hopital's rule, differentiate the numerator and denominator to get \( \frac{(n^2-1)x^{n^2-2}}{(n+1)x^n} \). Substituting x=1 yields \( \frac{n^2-1}{n+1} = n-1 \).
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