What is P(A) + P(B) + P(C) equal to ?
For the next three (03) items that follow : Let A, B, C and D be mutually exclusive and exhaustive events and \( \frac{P(A)}{2} = \frac{P(B)}{3} = \frac{P(C)}{5} = \frac{P(D)}{8} \).
- A. \frac{5}{9} ✓
- B. \frac{1}{18}
- C. \frac{2}{21}
- D. \frac{7}{13}
Correct Answer: A. \frac{5}{9}
Explanation
Let the ratio be k. P(A)=2k, P(B)=3k, P(C)=5k, P(D)=8k. Sum = 18k = 1, so k = 1/18. Then P(A)+P(B)+P(C) = 10k = 10/18 = 5/9.
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