What is \( \frac{[2P(A) + 3P(B)]}{[4P(C) + 5P(D)]} \) equal to ?

For the next three (03) items that follow : Let A, B, C and D be mutually exclusive and exhaustive events and \( \frac{P(A)}{2} = \frac{P(B)}{3} = \frac{P(C)}{5} = \frac{P(D)}{8} \).

  1. A. \frac{13}{18}
  2. B. \frac{13}{60} ✓
  3. C. \frac{4}{21}
  4. D. \frac{5}{28}

Correct Answer: B. \frac{13}{60}

Explanation

Substitute probabilities in terms of k: Numerator = 2(2k) + 3(3k) = 13k. Denominator = 4(5k) + 5(8k) = 60k. The ratio is 13/60.

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