If \frac{\cos \theta}{1 - \sin \theta} + \frac{\cos \theta}{1 + \sin \theta} = 4, then which one of the following is a value of (\tan^2 \theta + \cot^2 \theta) ?
- A. \frac{5}{3}
- B. \frac{10}{3} ✓
- C. 4
- D. 5
Correct Answer: B. \frac{10}{3}
Explanation
Simplifying the given equation yields \frac{2\cos\theta}{\cos^2\theta} = 4, so \cos\theta = \frac{1}{2}, which means \theta = 60^\circ. Therefore, \tan^2 60^\circ + \cot^2 60^\circ = 3 + \frac{1}{3} = \frac{10}{3}.
Related questions on Trigonometry
- Two poles are situated 24 m apart and their heights differ by 10 m. What is the distance between their tips?
- For 0 < \theta < \frac{\pi}{2}, consider the following : I. $(\tan^4 \theta + \tan^6 \theta)(\cot^4 \theta + \cot^6 \theta) = \sec^2 \the...
- If 3\sin \theta + 4\cos \theta = 5, then what is a value of 4\tan \theta + 3\cot \theta ?
- At a point on level ground, the tangent of the angle of elevation of the top of a tower is found to be \frac{5}{6}. On walking 70 m toward...
- Two persons are on diametrically opposite sides of a tower. They measure the angles of elevation of the top of the tower as 30^\circ and $...