Two poles are situated 24 m apart and their heights differ by 10 m. What is the distance between their tips?

Explanation

The distance between the tips forms the hypotenuse of a right-angled triangle where the base is the distance between the poles (24 m) and the altitude is the difference in their heights (10 m). Distance = \sqrt{24^2 + 10^2} = \sqrt{576 + 100} = \sqrt{676} = 26 m.

Related questions on Trigonometry

• If \frac{\cos \theta}{1 - \sin \theta} + \frac{\cos \theta}{1 + \sin \theta} = 4, then which one of the following is a value of $(\tan^2 \...
• For 0 < \theta < \frac{\pi}{2}, consider the following : I. $(\tan^4 \theta + \tan^6 \theta)(\cot^4 \theta + \cot^6 \theta) = \sec^2 \the...
• If 3\sin \theta + 4\cos \theta = 5, then what is a value of 4\tan \theta + 3\cot \theta ?
• At a point on level ground, the tangent of the angle of elevation of the top of a tower is found to be \frac{5}{6}. On walking 70 m toward...
• Two persons are on diametrically opposite sides of a tower. They measure the angles of elevation of the top of the tower as 30^\circ and $...