What is the <strong>MAXIMUM</strong> value of p?
Consider the following for the two (02) items that follow : Let p=|\sin \alpha-\sin(\alpha-90^{\circ})|.
- A. 1
- B. \sqrt{2} ✓
- C. \sqrt{3}
- D. 2
Correct Answer: B. \sqrt{2}
Explanation
Since p = |\sqrt{2}\sin(\alpha+45^{\circ})|, and the maximum value of the sine function is 1, the maximum value of p is \sqrt{2}(1) = \sqrt{2}.