What is the <strong>MAXIMUM</strong> value of p?

Consider the following for the two (02) items that follow : Let p=|\sin \alpha-\sin(\alpha-90^{\circ})|.

  1. A. 1
  2. B. \sqrt{2}
  3. C. \sqrt{3}
  4. D. 2

Correct Answer: B. \sqrt{2}

Explanation

Since p = |\sqrt{2}\sin(\alpha+45^{\circ})|, and the maximum value of the sine function is 1, the maximum value of p is \sqrt{2}(1) = \sqrt{2}.

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