What is \tan^2 \alpha equal to?

Consider the following for the three (03) items that follow : Let p=\tan 2\alpha-\tan \alpha and q=\cot \alpha-\cot 2\alpha.

  1. A. (pq)/(p+q)
  2. B. (p+2q)/p
  3. C. p/(p+2q)
  4. D. p/(2p+q)

Correct Answer: C. p/(p+2q)

Explanation

From the first question, p/q = \tan \alpha \tan 2\alpha = \tan \alpha \left(\frac{2\tan \alpha}{1-\tan^2 \alpha}\right) = \frac{2\tan^2 \alpha}{1-\tan^2 \alpha}. Let x = \tan^2 \alpha. Then p/q = \frac{2x}{1-x} \implies p - px = 2qx \implies p = x(p+2q) \implies x = \frac{p}{p+2q}.

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