What is \frac{p^2-q^2}{p^2+q^2} equal to?

For the following two (02) items: Let \sin A + \sin B = p and \cos A + \cos B = q.

  1. A. \cos(A+B)
  2. B. \cos(A-B)
  3. C. \cos(\frac{\pi}{2}-A-B)
  4. D. \cos(\pi-A-B)

Correct Answer: D. \cos(\pi-A-B)

Explanation

Using the formulas for p and q, p^2+q^2 = 4\cos^2(\frac{A-B}{2}) and p^2-q^2 = 4\cos^2(\frac{A-B}{2}) [\sin^2(\frac{A+B}{2}) - \cos^2(\frac{A+B}{2})] = -4\cos^2(\frac{A-B}{2})\cos(A+B). Thus, the ratio is -\cos(A+B) = \cos(\pi-A-B).

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