What is \frac{p^2+q^2}{p^2q^2} equal to?
For the following two (02) items: Let p = \csc 20^\circ and q = \csc 70^\circ.
- A. 1/2
- B. 1 ✓
- C. 3/2
- D. 2
Correct Answer: B. 1
Explanation
The expression simplifies to \frac{1}{q^2} + \frac{1}{p^2}. Substitute the definitions to get \sin^2 70^\circ + \sin^2 20^\circ. Since \sin 70^\circ = \cos 20^\circ, this is \cos^2 20^\circ + \sin^2 20^\circ = 1.