If \( p, q, r \) are the cube roots of unity, then what is \( \begin{vmatrix} p^2+q^2 & r^2 & r^2 \\ p^2 & q^2+r^2 & p^2 \\ q^2 & q^2 & r^2+p^2 \end{vmatrix} \) equal to ?

  1. A. -1
  2. B. 0
  3. C. 1
  4. D. 4

Correct Answer: D. 4

Explanation

The standard expansion for this determinant is 4p^2q^2r^2. Since p, q, r are cube roots of unity (1, \omega, \omega^2), their product pqr = 1. Therefore, the determinant evaluates to 4(1)^2 = 4.

Related questions on Matrices & Determinants

Practice more NDA Mathematics questions