In a triangle ABC, $ \sin A = \cos B + \cos C $ then what is $ \tan\left({2}\right) + \cot\left({2}\right) $ equal to ?

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2. By solving \sin A = \cos B + \cos C for a triangle, we get B = 90^\circ or C = 90^\circ. Assuming B = 90^\circ, 	an(45^\circ) + \cot(45^\circ) = 1 + 1 = 2.

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In a triangle ABC, \( \sin A = \cos B + \cos C \) then what is \( \tan\left(\frac{B}{2}\right) + \cot\left(\frac{B}{2}\right) \) equal to ?

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