What is the <strong>LEAST</strong> value of 9 \sin^{2}\theta + 16 \cos^{2}\theta?
- A. 0
- B. 9 ✓
- C. 16
- D. 25
Correct Answer: B. 9
Explanation
Rewrite the expression as 9\sin^2\theta + 16(1-\sin^2\theta) = 16 - 7\sin^2\theta. To find the least value, we must maximize \sin^2\theta, which has a maximum value of 1. Thus, the least value is 16 - 7(1) = 9.
Related questions on Trigonometry
- Two poles are situated 24 m apart and their heights differ by 10 m. What is the distance between their tips?
- If \frac{\cos \theta}{1 - \sin \theta} + \frac{\cos \theta}{1 + \sin \theta} = 4, then which one of the following is a value of $(\tan^2 \...
- For 0 < \theta < \frac{\pi}{2}, consider the following : I. $(\tan^4 \theta + \tan^6 \theta)(\cot^4 \theta + \cot^6 \theta) = \sec^2 \the...
- If 3\sin \theta + 4\cos \theta = 5, then what is a value of 4\tan \theta + 3\cot \theta ?
- At a point on level ground, the tangent of the angle of elevation of the top of a tower is found to be \frac{5}{6}. On walking 70 m toward...