If 0 \leq \alpha, \beta \leq 90^\circ such that \cos(\alpha-\beta)=1, then what is \sin \alpha - \sin \beta + \cos \alpha - \cos \beta equal to?

Explanation

Since \cos(\alpha-\beta) = 1, the angle (\alpha-\beta) must be 0^\circ. Therefore, \alpha = \beta. Substituting \alpha for \beta in the expression gives \sin\alpha - \sin\alpha + \cos\alpha - \cos\alpha = 0.

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