From an aeroplane flying above a river at an altitude of 1200 m, it is observed that the angles of depression of opposite points on the two banks of a river are 30^{\circ} and \theta. If the width of the river is 3000 m, then which one of the following is correct?

  1. A. \theta \lt 30^{\circ}
  2. B. 30^{\circ} \lt \theta \lt 45^{\circ}
  3. C. 45^{\circ} \lt \theta \lt 60^{\circ}
  4. D. 60^{\circ} \lt \theta \lt 90^{\circ}

Correct Answer: C. 45^{\circ} \lt \theta \lt 60^{\circ}

Explanation

The horizontal distance to the first bank is 1200 \cot 30^{\circ} = 1200\sqrt{3} \approx 2078.4 m. The remaining distance to the second bank is 3000 - 2078.4 = 921.6 m. Thus, \cot \theta = \frac{921.6}{1200} \approx 0.768. Since \cot 60^{\circ} \approx 0.577 and \cot 45^{\circ} = 1, the angle \theta lies between 45^{\circ} and 60^{\circ}.

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