If x=\frac{1-\cos \theta+\sin \theta}{1+\sin \theta}, then what is \frac(\sin \theta+\cos \theta-1)(\cos \theta) equal to?

Explanation

Let us check by value substitution. For \theta = 0^\circ: x = \frac{1-1+0}{1+0} = 0. The expression \frac{0+1-1}{1} = 0. Hence, the value of the expression is equivalent to x.

Related questions on Trigonometry

• Two poles are situated 24 m apart and their heights differ by 10 m. What is the distance between their tips?
• If \frac{\cos \theta}{1 - \sin \theta} + \frac{\cos \theta}{1 + \sin \theta} = 4, then which one of the following is a value of $(\tan^2 \...
• For 0 < \theta < \frac{\pi}{2}, consider the following : I. $(\tan^4 \theta + \tan^6 \theta)(\cot^4 \theta + \cot^6 \theta) = \sec^2 \the...
• If 3\sin \theta + 4\cos \theta = 5, then what is a value of 4\tan \theta + 3\cot \theta ?
• At a point on level ground, the tangent of the angle of elevation of the top of a tower is found to be \frac{5}{6}. On walking 70 m toward...