What is \sin^{2}A+\sin^{2}B+\sin^{2}C equal to?

Explanation

Since \angle C = 90^\circ, \sin C = 1. Also, A and B are complementary angles, meaning \sin B = \cos A. The expression evaluates to \sin^2 A + \cos^2 A + 1^2 = 1 + 1 = 2.

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