If x=\frac{1+\sin \theta}{\cos \theta}, then what is \frac{\tan \theta+\sec \theta-1}{\tan \theta-\sec \theta+1} equal to?

Explanation

The expression \frac{\tan\theta+\sec\theta-1}{\tan\theta-\sec\theta+1} is a standard trigonometric identity that simplifies to \tan\theta + \sec\theta. This equals \frac{\sin\theta}{\cos\theta} + \frac{1}{\cos\theta} = \frac{1+\sin\theta}{\cos\theta}, which is given as x.

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