What is 2 \sin^{6}\theta+2 \cos^{6}\theta-3 \sin^{4}\theta-3 \cos^{4}\theta equal to?

Explanation

Since the expression is independent of \theta, substitute \theta = 0^{\circ}. Thus, \sin 0^{\circ} = 0 and \cos 0^{\circ} = 1. The expression becomes 2(0) + 2(1) - 3(0) - 3(1) = 2 - 3 = -1.

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