Triangle ABC is right-angled at C and AC=\sqrt{3}BC. What is \angle ABC equal to?
- A. 30^\circ
- B. 45^\circ
- C. 60^\circ ✓
- D. 75^\circ
Correct Answer: C. 60^\circ
Explanation
In \triangle ABC right-angled at C, \tan(\angle ABC) = \frac{\text{Opposite}}{\text{Adjacent}} = \frac{AC}{BC}. Given AC = \sqrt{3}BC, we get \tan(\angle ABC) = \sqrt{3}. Therefore, \angle ABC = 60^\circ.
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