What is the value of (1+\cot^{2}\theta)(1+\cos\theta)(1-\cos\theta) - (1+\tan^{2}\theta)(1+\sin\theta)(1-\sin\theta)?

  1. A. -1
  2. B. 0
  3. C. 1
  4. D. 2

Correct Answer: B. 0

Explanation

The first term simplifies to \csc^2\theta(1-\cos^2\theta) = \csc^2\theta \sin^2\theta = 1. The second term simplifies to \sec^2\theta(1-\sin^2\theta) = \sec^2\theta \cos^2\theta = 1. The difference is 1 - 1 = 0.

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