If x\sin^{3}\theta+y\cos^{3}\theta=\sin \theta \cos \theta and x\sin \theta-y\cos \theta=0, for every \theta\in(0,\frac{\pi}{2}) then what is x^{2}+y^{2} equal to?
- A. 0
- B. 1 ✓
- C. 2
- D. 3
Correct Answer: B. 1
Explanation
From x\sin\theta = y\cos\theta, we get x = y\frac{\cos\theta}{\sin\theta}. Substitute this into the first equation: (y\frac{\cos\theta}{\sin\theta})\sin^3\theta + y\cos^3\theta = \sin\theta\cos\theta \implies y\cos\theta\sin^2\theta + y\cos^3\theta = \sin\theta\cos\theta \implies y\cos\theta(\sin^2\theta+\cos^2\theta) = \sin\theta\cos\theta. Thus, y\cos\theta = \sin\theta\cos\theta \implies y = \sin\theta. Consequently, x = \cos\theta. Therefore, x^2+y^2 = \cos^2\theta+\sin^2\theta = 1.
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