For how many values of \alpha does the expression (\sin \alpha+2)(\sin \alpha+4)(\sin \alpha-2)(\sin \alpha-4) become zero?

  1. A. No value
  2. B. One
  3. C. Two
  4. D. Four

Correct Answer: A. No value

Explanation

The expression equals zero if \sin \alpha \in \{-4, -2, 2, 4\}. Since the range of \sin \alpha is [-1, 1], there is no real value of \alpha that satisfies this condition.

Related questions on Trigonometry

Practice more CDS Elementary Mathematics questions