What is \tan \theta equal to?
For the following two (02) items: Let \frac{1+\sin \theta}{\cos \theta} = p + \sqrt{p^2+1}.
- A. p ✓
- B. \sqrt{p^2 + 1}
- C. \frac{1}{\sqrt{p^2 + 1}}
- D. \frac{p}{\sqrt{p^2 + 1}}
Correct Answer: A. p
Explanation
Subtracting \sec \theta - \tan \theta = \sqrt{p^2+1} - p from \sec \theta + \tan \theta = \sqrt{p^2+1} + p yields 2\tan \theta = 2p, which means \tan \theta = p.
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