What is \tan \theta + \cot \theta equal to?

For the following two (02) items: Let \sin \theta + \cos \theta = p and \sec \theta + \operatorname{cosec} \theta = q, where p \neq 1.

  1. A. p/q
  2. B. q/p
  3. C. 2p/q
  4. D. 2q/p

Correct Answer: B. q/p

Explanation

\tan \theta + \cot \theta = \frac{\sin^2 \theta + \cos^2 \theta}{\sin \theta \cos \theta} = \frac{1}{\sin \theta \cos \theta}. From the previous equations, q = \frac{p}{\sin \theta \cos \theta}, so \frac{1}{\sin \theta \cos \theta} = \frac{q}{p}.

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