What is the ratio of their 10th terms?
Consider the following for the next three (03) items that follow : Let P be the sum of first n positive terms of an increasing arithmetic progression A. Let Q be the sum of first n positive terms of another increasing arithmetic progression B. Let P:Q=(5n+4):(9n+6)
- A. 11/29
- B. 22/49
- C. 33/59 ✓
- D. 44/69
Correct Answer: C. 33/59
Explanation
To find the ratio of the 10th terms (m=10), we substitute n = 2(10)-1 = 19 into the formula for the ratio of the sum of n terms. The ratio is \frac{5(19)+4}{9(19)+6} = \frac{95+4}{171+6} = \frac{99}{177} = \frac{33}{59}.
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