What is \sum_{n=1}^{34}a_{n} equal to ?
Consider the following for the next two (02) items that follow : Let a_1, a_2, a_3 \dots be in AP such that a_{1}+a_{5}+a_{10}+a_{15}+a_{20}+a_{25}+a_{30}+a_{34}=300.
- A. 900
- B. 1025
- C. 1200
- D. 1275 ✓
Correct Answer: D. 1275
Explanation
The sum of the first 34 terms is given by S_{34} = \frac{n}{2}(a_1 + a_{34}). From the previous question's working, we know a_1 + a_{34} = 75. Thus, S_{34} = \frac{34}{2} \times 75 = 17 \times 75 = 1275.
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